 |
Zen and the Art of
Neutralization Calorimetry |
Purpose:
A neutralization reaction is the reaction between an acid and a base to produce water
and a salt. A salt is another name for an ionic compound and the specific salt produced
depends on the acid and base involved.
| Acid + Base à Water + Salt |
| Example: 2 HCl(aq) + Mg(OH)2(aq)
à 2 H2O(l) + MgCl2(aq) |
The product solution is neutral while the starting solutions are acidic
and basic respectively. A complete neutralization reaction requires an exact
stoichiometric ratio of the reactants and is termed the "equivalence
point". In the example above, neutralization requires a ratio of 2 moles of HCl
to react with exactly 1 mole of Mg(OH)2 at the equivalence point. An
excess of either the acid or base would result in a solution which is not neutral and not
at the equivalence point.
All reactions involve changes in energy. Neutralization reactions typically give
off relatively large amounts of energy as heat since the products are more stable (i.e.
lower in energy) than the reactants. The purpose of this lab is to ascertain, if possible,
the equivalence point of a neutralization reaction for an unknown acid and base by
examining the energy changes involved.
Technique:
Thermochemistry is the study of heat exchange or heat transfer. You will use a simple
calorimeter to measure the heat transfer (q) for a series of reactions. This data will be
examined to determine the equivalence point for a neutralization reaction.
A calorimeter can be used to determine the energy given off by a particular reaction.
The temperature inside the calorimeter is monitored and can be related to the energy
produced by the reaction. Any energy given off by the reaction will be used to heat any
substances in contact with the reaction such as the solvent and the calorimeter.
This is expressed mathematically below.
| heat lost = heat gain |
| q (reaction system) = -q (surroundings) |
The heat gained or lost is related to the mass of the material, the specific heat of
that substance, and the change in temperature observed. This can be expressed
mathematically (below) for a reaction occurring at constant atmospheric pressure.
| q = m * Csp * DT |
(m = mass, Csp = specific heat, T = temperature) |
We can assume the mass and composition of the
calorimeter will remain constant throughout the experiment. The above equation then
simplifies to q = Ccal * DT for the heat exchange with the calorimeter.
For the solutions you will be analyzing, the heat exchange will also involve the bulk
solution. The sum of these two components will be equal to the heat generated
by the reaction of interest.
qrxn
= Ccal * DT +
m * Csp * DT |
|
The Experiment: |
 |
- Calibration of the calorimeter: Use the procedure for
determining the heat capacity of a calorimeter provided on the CHEM 1102 web page
under " Enthalpy Change for a
Chemical Reaction" and discussion provided therein. The method is described
immediately under the "Procedure" heading in this document. Note that you
will be working alone and you will use the calibrated "cool water" calorimeter
for the remainder of this experiment. Follow the directions up to step #1
in that procedure and then continue on with step #2 below.
Accurately measure out about 30 mL of water and place it into the calorimeter. (What
measuring device is appropriate for measurement of volume in this experiment?
Consider accuracy and rate of delivery.) Cover the calorimeter with the top provided and
record the temperature of the water once it has stabilized at room temperature.
Accurately measure out 20 mL of a single unknown acid, record the I.D. and
concentration provided on the bottle, allow it to stabilize at room temperature
("initial temp."), and add it to the calorimeter. WARNING:
Always add acid or base to water and not the reverse! Record the
temperature of the solution every 60 seconds until the temperature stablilizes. Be
sure to gently swirl the calorimeter solution to distribute the heat throughout the
calorimeter or the temperature readings may be misleading. Note that
thermometers are fragile and make terribly expensive stirring rods in terms of time and
money! Plot temperature against time and use a straight line to extrapolate
your results back to the time of mixing (time = 0 sec.). This is the "final
temperature". Calculate the heat exchange for this dissolution process. What
physical constants are needed and where can you find these values? Can any
helpful assumptions or approximations be made?
- Repeat step 2 using 20 mL of a single unknown base in place of the acid. How do
these values compare to the acid results?
- Decide on a series of at least 5 trials that will allow you to probe the equivalence
point of the reaction between the acid and the base you chose in steps 2 and 3.
These trials should be done as similar as possible to the dissolution
reactions performed in steps 2 and 3 above. Keep the total volume of solution
constant at 50 mL (vol. acid + vol. base + vol. water). Choose differing volumes of
acid and base such that the ratio of acid/base covers a reasonably wide
stoichiometric range and the volume of acid +volume of base is always 20
mL. (What is the purpose of these experimental restraints?) Create a table showing
the volume of acid, volume of base, and volume of water to be used in each trial.
Now,
carry out your designed trials and determine the heat exchange (q) for each. It will
be difficult to mix three solutions (acid +base+water) at once. How should you
combine the solutions to make a safe and accurate measurement? If you first
dissolve the acid or base with the largest heat of dissolution in water and allow the
temperature to stabilize, you will only have to consider heat contributions from the
second dissolution reaction and the neutralization reaction. In addition, the second
dissolution reaction will likely only make a very small contribution to the total heat
exchange.
qdissolve
+ qneutral = Ccal * DT + m * Csp * DT |
- Calculate the heat, q, for each trial reaction you carried out in step 4.
Make a graph of qneutralization versus the ratio of (moles acid) / (moles base)
and determine the equivalence point molar ratio. What do you anticipate the shape of this
curve should look like? Why?
- For your conclusions, report your equivalence point ratio of moles of acid / moles of
base for the unknowns you used. How does q for the neutralization reaction differ
from q of the dissolution reactions done in steps 2 and 3? What effect do these
values have on determining the equivalence point? Does the ratio of acid / base you
obtained make chemical sense in terms of real molecules? Why or why not?
There are many sources of error in this experiment. What sources of error
might have affected your results?
Created by Shane Phillips.
Last edited on 10/30/98.